Then, we can just find the mass of 2.272 carbon atoms by multiplying 2.272 by the mass of 1 mole of carbon: 2.272 xx 12.01 = "27.29g" Since there was 1 significant figure in the question, our answer is …

Explanation: #M_ (CO_2) = "220 mg"# #MW_ (CO_2) = "44.01 g/mol"# #"O"_2 " molecules = ?"#

Comparing the intensity levels of two different sounds of intensities I_1 and I_2, IL_2 - IL_1 = (10 dB) [\log_ {10} (I_2/I_0) - \log_ {10} (I_1/I_0)] But, \qquad \log_ {10} (a) - \log_ {10} (b) = \log_ {10} (a/b) …

0.56 1 molar solution ="Number of moles of solute"/"Volume of solution" for Sugar C_ (12)H_ (22)O_ (11) molar mass=342gm according to equation and information provided 1= (3.42/342)/x where x is …

(a+b)^2=24.01 >"note that " (a+b)^2=a^2+2ab+b^2 color (white) (xxxxx)=a^2+b^2+2ab color (white) (xxxxx)=12.85+ (2xx5.58) color (white) (xxxxx)=12.85+11.16=24.01

Oct 11, 2015 · 1545 subjects were given ginko & 1524 placebo. In ginko group, 246 developed dementian & in the placebo it was 277 with dementia. Significance level=0.01 to test claim (ginko is …

The pendulum reaches a displacement of 10mm in 0.0314 s after crossing the equilibrium point. The frequency is 5 Hz and the amplitude is 0.012 m. One function that could result in the described …

Please see the explanation below The equation is y=2x^2+2 Compare this equation to y=ax^2+bx+c The coefficient of x^2 is a=2 >0 So the curve is convex. Now, calculate the intercepts with the y-axis x=0, …

Using the isotopic masses and their relative abundance, the average atomic mass comes out to 24.3051 u . You work this out as a weighted average. Each isotope's mass is multiplied by its relative …

log (0.01^2/x^3) = -10.64 I assume that log means the logarithm with base 10. By the property log (a/b)=log (a)-log (b) we get: log (0.01^2) - log (x^3) = -10.64 log ...